Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (2024)

Engage NY Eureka Math 4th Grade Module 3 Lesson 26 Answer Key

Eureka Math Grade 4 Module 3 Lesson 26 Problem Set Answer Key

Question 1.
Draw place value disks to represent the following problems. Rewrite each in unit form and solve.

a. 6 ÷ 2 = ____3____
6 ones ÷ 2 = ___3____ ones
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (1)
Answer:
6 ÷ 2 = 3
6 ones ÷ 2 = 3 ones,

Explanation:
Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 6 ÷ 2 = 3,
6 ones ÷ 2 = 3 ones.

b. 60 ÷ 2 = ________
6 tens ÷ 2 = ________
Answer:
60 ÷ 2 = 30
6 tens ÷ 2 = 3 tens,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (2)

Explanation:
Drawn place value disks to represent the following problems.
Rewrote each in unit form and solved as 60 ÷ 2 = 30,
6 tens ÷ 2 = 3 tens.

c. 600 ÷ 2 = __300______
_____6 hundreds______ ÷ 2 = ____3 hundreds____
Answer:
600 ÷ 2 = 300,
6 hundreds ÷ 2 = 3 hundreds,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (3)

Explanation:
Drawn place value disks to represent the following problems.
Rewrote each in unit form and solved as 600 ÷ 2 = 300,
6 hundred ÷ 2 = 3 hundred.

d. 6,000 ÷ 2 = ___3,000_____
__6 thousands_____ ÷ 2 = ____3 thousands______
Answer:
6000 ÷ 2 = 3,000,
6 thousands ÷ 2 = 3 thousands,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (4)

Explanation:
Drawn place value disks to represent the following problems.
Rewrote each in unit form and solved as 6,000 ÷ 2 = 3,000,
6 thousands ÷ 2 = 3 thousands.

Question 2.
Draw place value disks to represent each problem. Rewrite each in unit form and solve.
a. 12 ÷ 3 = ___4_____
12 ones ÷ 3 = _____4____ ones
Answer:
12 ÷ 3 = 4,
12 ones ÷ 3 = 4 ones,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (5)

Explanation:
Drawn place value disks to represent each problem. Rewrote each in unit form and solved 12 ÷ 3 = 4,
12 ones ÷ 3 = 4 ones.

b. 120 ÷ 3 = __40______
____12 tens______ ÷ 3 = __4 tens___
Answer:
120 ÷ 3 = 40,
12 tens ÷ 3 = 4 tens,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (6)

Explanation:
Drawn place value disks to represent each problem.
Rewrote each in unit form and solved 120 ÷ 3 = 40,
12 tens ÷ 3 = 4 tens.

c. 1,200 ÷ 3 = ____400____
____12 hundreds______ ÷ 3 = __4 hundreds____
Answer:
1,200 ÷ 3 = 400,
12 hundreds ÷ 3 = 4 hundreds,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (7)
Explanation:
Drawn place value disks to represent each problem.
Rewrote each in unit form and solved 1,200 ÷ 3 = 400,
12 hundreds ÷ 3 = 4 hundreds.

Question 3.
Solve for the quotient. Rewrite each in unit form.
a. 800 ÷ 2 = 400
8 hundreds ÷ 2 = 4 hundreds
Answer:
800 ÷ 2 = 400,
8 hundreds ÷ 2 = 4 hundreds,

b. 600 ÷ 2 = ____300____
Answer:
Solved for the quotient, Rewrote each in unit form as
600 ÷ 2 = 300,
6 hundreds ÷ 2 = 3 hundreds,

c. 800 ÷ 4 = ___200_____
Answer:
Solved for the quotient, Rewrote each in unit form as
800 ÷ 4 = 200,
8 hundreds ÷ 4 = 2 hundreds,

d. 900 ÷ 3 = __300_____
Answer:
900 ÷ 3 = 300,
9 hundreds ÷ 3 = 3 hundreds,

e. 300 ÷ 6 = ____50_____
30 tens ÷ 6 = __5__ tens
Answer:
300 ÷ 6 = 50,
30 tens ÷ 6 = 5 tens,

f. 240 ÷ 4 = ___60_____
Answer:
240 ÷ 4 = 60,
24 tens ÷ 4 = 6 tens,

g. 450 ÷ 5 = ___90_____
Answer:
450 ÷ 5 = 90,
45 tens ÷ 5 = 9 tens,

h. 200 ÷ 5 = ___40____
Answer:
200 ÷ 5 = 40,
20 tens ÷ 5 = 4 tens,

i. 3,600 ÷ 4 = ___900_____
36 hundreds ÷ 4 = __9__ hundreds
Answer:
3,600 ÷ 4 = 900,
36 hundreds ÷ 4 = 9 hundreds,

j. 2,400 ÷ 4 = ___600_____
Answer:
2,400 ÷ 4 = 600,
24 hundreds ÷ 4 = 6 hundreds,

k. 2,400 ÷ 3 = ____800___
Answer:
2,400 ÷ 3 = 800,
24 hundreds ÷ 3 = 8 hundreds,

l. 4,000 ÷ 5 = __800____
Answer:
4,000 ÷ 5 = 800,
40 hundreds ÷ 5 = 8 hundreds,

Question 4.
Some sand weighs 2,800 kilograms. It is divided equally among 4 trucks. How many kilograms of sand are in each truck?
Answer:
700 kilograms of sand are there in each truck,

Explanation:
Given some sand weighs 2,800 kilograms. It is divided equally among 4 trucks.
Number of kilograms of sand are there in each truck is 2,800 kilograms ÷ 4 = 700 kilograms.
Therefore 700 kilograms of sand are there in each truck.

Question 5.
Ivy has 5 times as many stickers as Adrian has. Ivy has 350 stickers. How many stickers does Adrian have?
Answer:
Adrian have 70 stickers,

Explanation:
Given Ivy has 5 times as many stickers as Adrian has.
Ivy has 350 stickers. Number of stickers does Adrian have are 350 stickers ÷ 5 = 70 stickers, therefore Adrian have 70 stickers.

Question 6.
An ice cream stand sold $1,600 worth of ice cream on Saturday, which was 4 times the amount sold on Friday. How much money did the ice cream stand collect on Friday?
Answer:
On Friday the ice cream stand collected $400,

Explanation:
Given an ice cream stand sold $1,600 worth of ice cream on Saturday, which was 4 times the amount sold on Friday.
So money did the ice cream stand collected on Friday is
$1,600 ÷ 4 = $400.

Eureka Math Grade 4 Module 3 Lesson 26 Exit Ticket Answer Key

Question 1.
Solve for the quotient. Rewrite each in unit form.
a. 600 ÷ 3 = 200
6 hundreds ÷ 3 = __2__ hundreds
Answer:
600 ÷ 3 = 200,
6 hundreds ÷ 3 = 2 hundreds,

b. 1,200 ÷ 6 = ___200____
Answer:
1,200 ÷ 6 = 200,
12 hundreds ÷ 6 = 2 hundreds,

c. 2,100 ÷ 7 = __300_____
Answer:
2,100 ÷ 7 = 300,
21 hundreds ÷ 7 = 3 hundreds,

d. 3,200 ÷ 8 = _400____
Answer:
3,200 ÷ 8 = 400,
32 hundreds ÷ 8 = 4 hundreds,

Question 2.
Hudson and 7 of his friends found a bag of pennies. There were 320 pennies, which they shared equally. How many pennies did each person get?
Answer:
Each person will get 40 pennies,

Explanation:
Given Hudson and 7 of his friends found a bag of pennies. There were 320 pennies, which they shared equally.
So number of pennies did each person will get is 320 pennies ÷ 8 = 40 pennies each.

Eureka Math Grade 4 Module 3 Lesson 26 Homework Answer Key

Question 1.
Draw place value disks to represent the following problems.
Rewrite each in unit form and solve.
a. 6 ÷ 3 = ___2_____
6 ones ÷ 3 = ____2_____ones
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (8)
Answer:
6 ÷ 3 = 2
6 ones ÷ 3 = 2 ones,

Explanation:
Drawn place value disks to represent the following problems.
Rewrote each in unit form and solved as 6 ÷ 3 = 2,
6 ones ÷ 3 = 2 ones.

b. 60 ÷ 3 = ___20_____
6 tens ÷ 3 = ____2 tens__________
Answer:
60 ÷ 3 = 20
6 tens ÷ 3 = 2 tens,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (9)

Explanation:
Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 60 ÷ 3 = 20,
6 tens ÷ 3 = 2 tens.

c. 600 ÷ 3 = ___200_____
_____6 hundreds____ ÷ 3 =____2 hundreds_______
Answer:
600 ÷ 3 = 200,
6 hundreds ÷ 3 = 2 hundreds,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (10)

Explanation:
Drawn place value disks to represent each problem. Rewrote each in unit form and solved 600 ÷ 3 = 200,
6 hundreds ÷ 2 = 2 hundreds.

d. 6,000 ÷ 3 = __2,000______
_______6 thousands____ ÷ 3 = _______2 thousands_______
Answer:
6,000 ÷ 3 = 2,000,
6 thousands ÷ 3 = 2 thousands,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (11)

Explanation:
Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 6,000 ÷ 3 = 2,000,
6 thousands ÷ 3 = 2 thousands.

Question 2.
Draw place value disks to represent each problem. Rewrite each in unit form and solve.
a. 12 ÷ 4 = __3_____
12 ones ÷ 4 = _____3____ones
Answer:
12 ÷ 4 = 3,
12 ones ÷ 4 = 3 ones,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (12)

Explanation:
Drawn place value disks to represent each problem. Rewrote each in unit form and solved 12 ÷ 4 = 3,
12 ones ÷ 4 = 3 ones.

b. 120 ÷ 4 = ___30_____
_____12 tens____ ÷ 4 = __________3 tens___________
Answer:
120 ÷ 4 = 30,
12 tens ÷ 4 = 3 tens,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (13)

Explanation:
Drawn place value disks to represent each problem. Rewrote each in unit form and solved 120 ÷ 4 = 30,
12 tens ÷ 4 = 3 tens.

c. 1,200 ÷ 4 = ___300_____
____12 hundreds______ ÷ 4 = ___3 hundreds____
Answer:
1,200 ÷ 4 = 300,
12 hundreds ÷ 4 = 3 hundreds,
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (14)
Explanation:
Drawn place value disks to represent each problem. Rewrote each in unit form and solved 1,200 ÷ 4 = 300,
12 hundreds ÷ 4 = 3 hundreds.

Question 3.
Solve for the quotient. Rewrite each in unit form.
a. 800 ÷ 4 = 200
8 hundreds ÷ 4 = 2 hundreds
Answer:
800 ÷ 4 = 200,
8 hundreds ÷ 4 = 2 hundreds,

Explanation:
Solved for the quotient, Rewrote each in unit form as
800 ÷ 4 = 200,
8 hundreds ÷ 4 = 2 hundreds.

b. 900 ÷ 3 = ____300_____
Answer:
900 ÷ 3 = 300,
9 hundreds ÷ 3 = 3 hundreds,

c. 400 ÷ 2 = ___200_____
Answer:
400 ÷ 2 = 200,
4 hundreds ÷ 2 = 2 hundreds,

d. 300 ÷ 3 = __100___
Answer:
300 ÷ 3 = 100,
30 tens ÷ 3 = 10 tens,

e. 200 ÷ 4 = ___50______
20 tens ÷ 4 = _5___ tens
Answer:
200 ÷ 4 = 50,
20 tens ÷ 4 = 5 tens

f. 160 ÷ 2 = ____80_____
Answer:
160 ÷ 2 = 80,
16 tens ÷ 2 = 8 tens,

g. 400 ÷ 5 = __80______
Answer:
400 ÷ 5 = 80,
40 tens ÷ 5 = 8 tens,

Explanation:
Solved for the quotient, Rewrote each in unit form as
400 ÷ 5 = 80,
40 tens ÷ 5 = 8 tens.

h. 300 ÷ 5 = ___60_____
Answer:
300 ÷ 5 = 60,
30 tens ÷ 5 = 6 tens

i. 1,200 ÷ 3 = ___400______
12 hundreds ÷ 3 = _4___ hundreds
Answer:
1,200 ÷ 3 = 400,
12 hundreds ÷ 3 = 4 hundreds,

j. 1,600 ÷ 4 = ___400_____
Answer:
1,600 ÷ 4 = 400,
16 hundreds ÷ 4 = 4 hundreds

k. 2,400 ÷ 4 = ___600____
Answer:
2,400 ÷ 4 = 600,
24 hundreds ÷ 4 = 6 hundreds

l. 3,000 ÷ 5 = __600____
Answer:
3,000 ÷ 5 = 600,
30 hundreds ÷ 5 = 6 hundreds

Question 4.
A fleet of 5 fire engines carries a total of 20,000 liters of water. If each truck holds the same amount of water. how many liters of water does each truck carry?
Answer:
4,000 liters of water each truck carry,

Explanation:
Given a fleet of 5 fire engines carries a total of 20,000 liters of water.
If each truck holds the same amount of water.
The number of liters of water does each truck carry is
20,000 ÷ 5 = 4,000 liters.

Question 5.
Jamie drank 4 times as much juice as Brodie. Jamie drank 280 milliliters of juice. How much juice did Brodie drink?
Answer:
70 milliliters of juice Brodie drank,

Explanation:
Given Jamie drank 4 times as much juice as Brodie. Jamie drank 280 milliliters of juice.
So number of liters of juice did Brodie drank is 280 milliliters ÷ 4 = 70 milliliters.

Question 6.
A diner sold $2,400 worth of French fries in June, which was 4 times as much as was sold in May. How many dollars’ worth of French fries were sold at the diner in May?
Answer:
$600 dollars’ worth of French fries were sold at the diner in May,

Explanation:
Given a diner sold $2,400 worth of French fries in June, which was 4 times as much as was sold in May.
So number of dollars’ worth of French fries were sold at the diner in May is $2,400 ÷ 4 = $600.

Eureka Math Grade 4 Module 3 Lesson 26 Template Answer Key

thousandshundredstens

ones

_________1,000____________________________

thousands place value chart for dividing
Answer:
Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (15)
Explanation:
Thousands place value chart for dividing is as shown above while dividing 1,000, the digits will move right 3 spaces.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key (2024)

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In the division problem 86 \\/ 4, the correct answer is 21 with a remainder of 2. When dividing 86 by 4, you determine how many times 4 goes into 86 completely and evenly. Here, 4 goes into 86 a total of 21 times since 4 * 21 = 84. The number 84 is 2 less than 86, which gives us the remainder of 2.

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Why does Cayman say 94 3 is 30 with a remainder of 4? ›

Cayman says that 94 ÷ 3 is 30 with a remainder of 4. He reasons this is correct because (3 × 30) + 4 = 94.

Does 1 divided by 2 have a remainder? ›

So, write 0 below 1 and perform subtraction. The result is 1-0=1. Thus, when 1 is divided by 2, the remainder is 1.

What is 2 192 divided by 6? ›

We can observe that the remainders repeat after every 6 powers. Since 192 is divisible by 6 (192 ÷ 6 = 32), we can conclude that the remainder when 2^192 is divided by 6 is the same as the remainder when 2^6 is divided by 6, which is 2. Therefore, the remainder when 2^192 is divided by 6 is 2.

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The hardest math classes in high school are typically pre-calculus, Calculus, Algebra I, and II, and some advanced math concepts like statistics and trigonometry. These courses are challenging because they cover advanced mathematical concepts and require students to have a strong foundation in algebra and geometry.

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